Product of Array Except Self: time complexity O(n) vs O(n^2)
RAJESH, April 16, 2020
Problem – Product of Array Except Self
https://leetcode.com/problems/
Given an array nums
of n integers where n > 1, return an array output
such that output[i]
is equal to the product of all the elements of nums
except nums[i]
.
Example:
Input:[1,2,3,4]
Output:[24,12,8,6]
Constraint: It’s guaranteed that the product of the elements of any prefix or suffix of the array (including the whole array) fits in a 32 bit integer.
Note: Please solve it without division and in O(n).
Follow up:
Could you solve it with constant space complexity? (The output array does not count as extra space for the purpose of space complexity analysis.)
Group Anagrams ES6 solution
#1 O(n^2) time complexity solution
/** @param {number[]} nums @return {number[]} */ var productExceptSelf = function(nums) { let result = []; result[nums.length - 1] = 1; for(let i = nums.length - 2; i >= 0; i--){ result[i] = result[i + 1] * nums[i + 1]; } let left = 1; for(let i = 0; i < nums.length; i++){ result[i] = result[i] * left; left = left * nums[i]; } return result; }; productExceptSelf([-1,-1,1,-1,-1,1,-1,-1, ………50K])
runtime 140ms
#2 O(n) time complexity solution
/** @param {number[]} nums @return {number[]} */ var productExceptSelf = function(nums) { let result = []; result[nums.length - 1] = 1; for(let i = nums.length - 2; i >= 0; i--){ result[i] = result[i + 1] * nums[i + 1]; } let left = 1; for(let i = 0; i < nums.length; i++){ result[i] = result[i] * left; left = left * nums[i]; } return result; };
runtime 84ms